Recent content by iknowsigularity
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Special Relativity: Traveling to Regulus
I redid the numbers and got 0.89c. :D thank you so much so excited to finally understand this. Thanks for sticking with me.- iknowsigularity
- Post #22
- Forum: Introductory Physics Homework Help
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Special Relativity: Traveling to Regulus
So i drop c to 1 and plug in 40 and 77 for the values. i got 0.21 would this be in percent of the speed of light or is it wrong?- iknowsigularity
- Post #20
- Forum: Introductory Physics Homework Help
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Special Relativity: Traveling to Regulus
Thanks you so much! Sorry for the bad manners. Last question i would have is whether in this case you need to convert the units from lys to meters and years to seconds? i would assume so.- iknowsigularity
- Post #18
- Forum: Introductory Physics Homework Help
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Special Relativity: Traveling to Regulus
Solving for u: L0 *Sqrt(1-(u^2/c^2)) / u = t0 First square both sides giving us L0^2 / u^2 * (1-(u^2/c^2)) = t0^2 next we distribute the L0^2 / u^2 so we get L0^2 / u^2 - L0^2/c^2 = t0^2 (u^2 gets canceled out in the second term) so solving for u we get u^2 = L0^2 / (t0^2 + (L0^2/c^2))...- iknowsigularity
- Post #16
- Forum: Introductory Physics Homework Help
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Special Relativity: Traveling to Regulus
My apologies this question has given me a bad mood. Steps: Assuming we are in ship's inertial frame as the ship goes toward regulus, the time we see for the ship to make the trip should be equal to L1 (the contracted distance between the ship and regulus) / u (the velocity of the ship) aka...- iknowsigularity
- Post #14
- Forum: Introductory Physics Homework Help
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Special Relativity: Traveling to Regulus
I'm not trying to guess i am taking the course and i understand where the time dilation equation and length contraction equation come from, maybe it is as simple as saying 77lys / 40 years produces a speed over c so therefore it is not possible but i thought that maybe time dilation would have...- iknowsigularity
- Post #12
- Forum: Introductory Physics Homework Help
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Special Relativity: Traveling to Regulus
would the proper equation be u1 ^2 = L0^2/t1^2 * (1/(1-u0^2/c^2)) where u0 is just simply 77ly / 40 years? edit: nvm that can't be it either- iknowsigularity
- Post #10
- Forum: Introductory Physics Homework Help
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Special Relativity: Traveling to Regulus
Looking again i see that i did it wrong the problem I am having is dealing with the 1-u^2/c^2 i don't know how to separate the u out. I was defining t1 as 40 as its the number of years he would need to reach into be alive and L0 i defined as 77 light years.- iknowsigularity
- Post #9
- Forum: Introductory Physics Homework Help
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Special Relativity: Traveling to Regulus
So i solved for u^2 and got = L0/(t1^2(1-(1/c^2) but doing unit analysis gives me s^2 over m so this can't be correct :/- iknowsigularity
- Post #7
- Forum: Introductory Physics Homework Help
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Special Relativity: Traveling to Regulus
You square both sides correct? How do you deal with the u^2/c^2 though?- iknowsigularity
- Post #5
- Forum: Introductory Physics Homework Help
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Special Relativity: Traveling to Regulus
Assuming i sub t0 for L0/u then the only variable unknown is u but I am left with t1 = L0/u (1/(sqrt(1- (u^2/c^2))) and i don't know how to solve this for u. (Sorry I am on mobile so i can't add this to post)- iknowsigularity
- Post #3
- Forum: Introductory Physics Homework Help
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Special Relativity: Traveling to Regulus
Homework Statement A visit to Regulus is on my bucket list. However, it is 77 light years away. Assuming I will live only another 40 years, can I make it to Regulus? How fast would I have to travel (at constant speed) to get there in 40 years? Homework Equations t1 = t0...- iknowsigularity
- Thread
- Length contraction Modern physics Relativity Special relativity Time dialation
- Replies: 21
- Forum: Introductory Physics Homework Help
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Playground/merrygo round problem. Rotational kinematics
so would perhaps the conservation of kinetic energy formula work? or actually its the conservation of angular momentum so (moment of inertia)(angular speed) intial = (moment of inertia)(angular speed) final?- iknowsigularity
- Post #5
- Forum: Introductory Physics Homework Help
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Playground/merrygo round problem. Rotational kinematics
I assume possibly the conservation of angular momentum? and maybe you take the tangential speed of the child and transform it to angular speed?- iknowsigularity
- Post #3
- Forum: Introductory Physics Homework Help
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Playground/merrygo round problem. Rotational kinematics
Homework Statement In a playground there is a small merry-go-round of radius 1.20 m and mass 220 kg. The radius of gyration is 91.0 cm. A child of mass 44.0 kg runs at a speed of 3.00 m/s tangent to the rim of the merry-go-round when it is at rest and then jumps on. Neglect friction between the...- iknowsigularity
- Thread
- Kinematics Rotational Rotational kinematics
- Replies: 5
- Forum: Introductory Physics Homework Help