1st
lny=ln((sinx)^x)
lny=xln(sinx)
then take the derivative and use product and chain rule ;)
dy/dx(1/y)=x(1/sinx)cosx + ln(sinx)
then simplfy
dy/dx(1/y) = xcotx+lnsinx
dy/dx=y[xcotx+lnsinx]
plug in for y
dy/dx= (sinx)^x[xcotx+lnsinx]
message me if you need any explanations.
thanks for your advice.
If you do not mind me asking where is your firm located?
I'm curious to find out where most of the engineering firms are at.
is there allot in los angeles?
thannks
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i know SLO would be the best choice engineering in general.
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And I've been hearing that UCLA has a better engineering program. Is that true??
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