Recent content by Irishdoug

What area of physics are you interested in? You could look into quantum computing, for example, where having a CS degree isn't necessarily a disadvantage. There are masters in quantum technology (upon which quantum computing or better yet quantum information is a subfield) such as in Munich*...

Have you emailed your professor and asked for your exam transcript back? And asked him to go through it with you? Has he got office hours? Even go to his office and knock in and tell him you are having trouble with the class!

The solution can be viewed here on page 41 https://usermanual.wiki/Document/Steven20H20Simon2020The20Oxford20Solid20State20Basics2C20Solution20ManualOxford20University20Press202015.1463186034/view What I have is $$\frac{\partial}{\partial \phi^{*}} (\frac{\sum_{n,m} \phi_{n}^{*}...

Well what you have said sounds more reasonable. The integral is given as ##\int_{\-infty}^{\infty}## which is why I said what I did.

$$A_{average} = \frac{\int_{-\infty}^{\infty} A(p,q) \ e^{-\frac{E}{kT} }dp\,dq} {\int_{-\infty}^{\infty} e^{-\frac{E}{kT} }dp\,dq}\quad ?$$ Yes I meant this indeed. So I'm viewing it as follows: p = $$(p_{x1}, p_{y1}, p_{z1} ; p_{x2}, p_{y2}, p_{z2}... p_{xN}, p_{yN}...

Hi BvU. Thankyou for the response. I'm using Kittel's solid state book. Sorry I thought he only had that one. And yes I have the first edition (and the 7th!). I feel from a cursory glance he goes through the maths in a more understandable way in the first, at least in some sections. I am busy...

I'm happy I understand why the dq terms cancel out. So, $$E_{average} = U = \frac{\frac{1}{2M} \sum_{\alpha = 1}^{3N} p_{\alpha}^{2} \int_{-\infty}^{\infty} \Pi_{\beta = 1}^{3N} e^{\frac{-p_{\beta}^{2}}{2M k_{b}T} }dp}{\int_{-\infty}^{\infty} \Pi_{\beta = 1}^{3N} e^{\frac{-p_{\beta}^{2}}{2M...

Many entangled particle pairs are prepared with property A (1 or 0) at 99% probability of 1, and property B (1 or 0) at 1% probability of 1. I don't believe such a state would really be considered entangled.

If you are an undergraduate then no, provided you pass the repeats and do well in the proceeding years.

Just be aware in Scandinavia if you already have a masters then getting the government grant will not be an option as far as I know. So you will have to completely self-fund yourself. I'm 90% sure the above is correct but as ever best do your own research.

To work or study?

As a native English speaker, this will unlikely be the case. It may well be that one will be able to tell you are not a native speaker however it is unlikely they will be confused. From the short paragraphs you've written here your English seems fine as does your grammar. So I wouldn't worry...

No problem. If you've any questions don't hesitate to PM me.

If you want a concise overview of the type of maths you will need, you can buy (or google for a free PDF!) Mathematical Methods in the Physical Sciences by Mary L. Boas. To me, it's a classic, and a nice broad, yet not too difficult book.

Suggesting that the education system, and University you attended, is fundamentally racist makes it sound like you are trying to blame others for your own failures. As regards to other places to apply, have you tried Denmark? It isn't too difficult to get accepted once you have the minimum...