Recent content by iSimply

Oh and an edit my to North Component it should be = A wind (√3/2) (tcalm-tgust) since no north component was acting it on from t0 until tgust. You are awesome, thank you for the help!

Yeah it should be (tcalm - tgust) good catch. Well it goes from Vinit+ (motor(tgust-t0)) when the wind start. Then once it stop then wouldn't it be that plus ( motor + windcos 60)(tcalm-tgust). so it would be Vinit + (motor (tgust-t0))+ (motor +windcos 60)(t calm-tgust). Is that right?

No... :( That was the part where I was confused and wasn't sure how to approach it. I know that from t0 to tgust the motor was running, but I wasn't sure how to incorporate it. V east= Vinit + (motor (t0-tgust))+ (motor + wind)(tcalm-tgust)...

Well for the East component we have a Vinit and 2 acceleration component acting on it. Which are Amotor and Awind. And we know that Awind is 60 degree north east so the Awind in the east direction would be equal to Awindcos60degree So Velocity for the East component is equal to Vinit+ (Amotor +...

I wasn't sure if from t0 to Tgust there was a time difference. If the point where Tgust happens then it would only be from Tcalm-Tgust. Is the rest of it correct?

Homework Statement A sailboat is traveling due east, with a speed V=Vinit at time t = 0 and a constant eastward acceleration A(motor). From a time t = t(gust) to a time t=t(calm), a gust of wind gives the boat an additional acceleration A(wind) at an angle 60o North of East. Find an expression...