Recent content by iwsc
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Help with elastic collisions please
Alright, I got it! Thank you for the help!- iwsc
- Post #13
- Forum: Introductory Physics Homework Help
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Help with elastic collisions please
Sorry, I'm lost. I don't know what I'm supposed to be doing.- iwsc
- Post #10
- Forum: Introductory Physics Homework Help
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Help with elastic collisions please
Sorry, the v1' at the end was a typo. So then with v1 + v1' = v2' and m1(v1 - v1') =m2v2' which becomes (m1(v1 - v1')) / m2 = v2' I would do v2' = v2' to get v1 + v1' = (m1(v1 - v1')) / m2 v1' = ((m1(v1 - v1')) / m2 ) - v1 Is this correct? And from here, how do I go on to the wanted...- iwsc
- Post #8
- Forum: Introductory Physics Homework Help
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Help with elastic collisions please
Okay, that part I'm good with, but I still don't understand how to get those equations to v1'= ((m1-m2)/(m1+m2)) v1'.- iwsc
- Post #6
- Forum: Introductory Physics Homework Help
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Help with elastic collisions please
So: (m1(v1 - v1')(v1 + v1')) / m1(v1 - v1') = (m2v2'^2) / (m2v2') v1 + v1' = v2' ??- iwsc
- Post #4
- Forum: Introductory Physics Homework Help
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Help with elastic collisions please
After simplifying the equations, I got: m1(v1-v1') = m2v2' (momentum) and m1(v1-v1')(v1+v1') = m2v2'^2 (kinetic energy) From there, I'm not sure what to do. I referred to a textbook and it said to divide the energy equation by the momentum equation (the simplified versions) and then do a...- iwsc
- Thread
- Collisions Elastic Elastic collision Elastic collisions Momentum and energy Physics
- Replies: 12
- Forum: Introductory Physics Homework Help