Recent content by Jack Nagel

I'll be damned. Interesting http://en.wikipedia.org/wiki/Newton-second"

A Newton is equal to 1 kg*m/s^2 So I guess theoretically you could give momentum in Newton seconds (as this would effectively cancel one of the "seconds"), but that seems pointless to me.

Keep in mind that you're finding an equation for part (a), and not a number. As hage567 said showing some work would be beneficial to all.

F is not 9.8 m/s^2. That is a. You are forgetting to take into account mass of the skier. force = mass * acceleration

Say that {W1, W2, W3, W4} is linearly independent in R4. Now say I have this vector [ 2 tan(h) 7 4sec(k) ] and I want to find values of h and k such that it is not in the span of (W1...W4). If I understand this correctly, it means it is impossible to find those values since they do not...

Thanks, to both of you. That's the approach I was working on but I was curious to see if there was a different method available.

Homework Statement A box holding only pennies, dimes, and nickels contains 47 coins worth $3.53. How many of each type of coin are in the box?Homework Equations none reallyThe Attempt at a Solution Ok. So from the problem I can generate two equations: x1+x2+x3=47 and .01x1+.1x2+.05x3=3.53...