Recent content by jackkk_gatz

Yes it was a typo, fixed it already. And yes I have tried to get the the general solution by the method of separation of variables, the thing is I know how to apply it but with homogeneous BC where I do some things with Sturm-Liouville. The thing is Sturm-Liouville only works with homogeneous...

I just noticed I asked my question in the wrong section 💀

I did a change of variable $$\theta(r,z) = T(r,z)-T_{\infty}$$ which resulted in $$\frac{1}{r}\frac{\partial }{\partial r}(r\frac{\partial \theta}{\partial r})+\frac{\partial^2 \theta}{\partial z^2}=0$$ $$\left.-k\frac{\partial \theta}{\partial r}\right\rvert_{r=R}=h\theta$$...

This is the rest of things the problem asks for, in case it is important: Establish a mathematical model describing the energy balance along the rod as a function of temperature and the indicated physical and geometrical properties (do not forget the boundary conditions). In steady state...

hmm okayy, I think I understand now. I have a question, when the problem ask me to obtain axial temperature profile, what does it mean axial? Along the rod? In the radial direction?

Oh okay R in this case is resistance, the symbol used for resistivity is ##\rho##. And about the other thing, I see possible that temperature varies across the radius. But the problem mentiones that L>>R so I think I should give more importance to the length, as if the temperature variation...

I picked up that formula from the book Heat transfer by Cengel. L is in the denominator because what the formula is doing is computing the volumetric heat, so the volume for the cylinder is the one on the denominator. And the rod, I believe, that the temperature changes along the rod due to...

I know that ##\dot e_{gen} = \frac {R_{e}i^2} {\pi r^2 L}## the thing is I don't know the value of i. I didn't write it, but another thing that the problem asks is to determine the flow of electric current. The model I came up with using heat generation due to electrical current is $$ \frac...

what do you mean by gives a potential?

the problem ask two things, the first one is asking for the angular velocity for the cone to overflow, I already solved that, it was not a problem. The second one is the one that asks for the volumetric flow, which is the one that I wrote, the one I'm struggling with

I too am having difficulty understanding the question, because it is quite a few things that change. It makes sense and I think it is the right thing to think, that the volumetric flow is not constant, I don't understand what my professor meant at all. The only thing he told me when I asked him...

I solved the case where m=0.99999. Then the height at which it overflows can be obtained with the equation, when points on the liquid surface are chosen. Then the cross-sectional area is given by the circumference of the circle times the height that the parabola reaches, that cross-sectional...

##P+pg(H-h) =P(x) + v^2(x)p/2+pgh(x)## why the velocity at h is zero? I would think at the top the velocity is zero since it is not moving, not at H-h

Okay I see ##v_1(h-x\cos(\theta)) = (h-h\cos(\theta))\sqrt{2gH}## Is this what you meant? If this is correct ##v_1 =\frac {(h-h\cos(\theta))\sqrt{2gH}} {(h-x\cos(\theta))}## Then I use Bernoulli, P1 being at the top of the reservoir ##P_atm =P(x) + v(x)p/2+pgh(x)##

I guess I have to find h(x) with V1A1=V2A2, then use the bernoulli equation to find p(x). So I have ##v_1x\cos(\theta) = (h-h\cos(\theta))\sqrt{2gH}## Then I use this on the bernoulli equation to find p(x), the thing is, wouldn't I end up having two pressures? The first one being p(x) and the...