Recent content by Jaco Viljoen

((e^x)^2)-2=e^x (k^2)-k-2=0 k=e^x (k+1)(k-2)=0 k=-1 or k=+2 e^x=2 lne^x=ln2 x=ln2

Hi Mark, Thank you, I initially did this but how do I factor e^(x2) I also considered adding a ln to both sides to get rid of the e on both sides but the -2 is the problem.

Homework Statement h(x)=e^(2x)-2 a)Write down the Dh b)Solve the equation e^(2x)-2=e^x Homework EquationsThe Attempt at a Solution a)x∈ℝ[/B] e^(2x)-2=e^x ((e^x)^2)-e^x-2=0I don't know what to do here:

I did fix this it was a typo Yes it is

So where in my work did I go wrong? I am not sure I see the problem, would you mind showing me? Thank you RUber

Thank you,

I meant to say x>-5 so the root will not be of a negative number.

Oops, I've added my answer, Thank you,

Homework Statement g(x)=√(5+x)-x a) Write down D(g) b) Solve the equation √(5+x)-x=3 Homework Equations √(5+x)-x=3 The Attempt at a Solution a) x∈ℝ: x>-5 b)[/B] √(5+x)-x=3 √(5+x)=x+3 (5+x)=(x+3)^2 (5+x)=(x+3)(x+3) (5+x)=x^2+6x+9 x^2+5x+4=0 (x+4)(x+1) x=-4 or x=-1 √(5-4)--4=3 √(1)+4=3...

Good afternoon everyone, I am preparing for exams and thought I would post a couple old paper questions and answers for what I have done, As always I appreciate any input and feedback. Homework Statement The Function ƒ(x) = 6x^2+5x a) Write down the Dƒ b) Solve the inequality f(x) < 4...

Hi Dr Courtney, Thank you, I will check it out

Hi All, As some of you know I have started working towards a degree in Civil engineering at the age of 33. My math is quite rusty since finishing school in 2000 and not using math for 15 years. As you have seen I post quite a couple of questions on the forum and work through them with help of...

Hi Mark, Does this look correct?

g(x)-f(x)=d(x) g(x)-f(x) d(x)={(-1/2)x}-{(1/2)x^2+2x} d(x)=(-1/2)x^2-2&(1/2)x x=-b/2a x=(-(2&1/2)/(2(-1/2)) x=-2.5 d(x)=(-1/2)x^2-2&(1/2)x d(x)=(-1/2)(-2.5)^2-2&(1/2)(-2.5) d(x)=3.125 maximum vertical distance

I am not sure I understand what is expected of me? P is an intersection, so there is no difference in height? Surely the max vertical distance will be at the vertex or somewhere to the right? Am I misunderstanding this?