Recent content by Jakeus314
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Ask a Stupid Quetion Get a Stupid Answer
My first choice is to make their bunker out of cards, but it really depends on what 2012 wants their bunker to feel like. Feelings are, as we all know, the most important aspect of existence. Who exactly is this 2012 person anyway?- Jakeus314
- Post #3,419
- Forum: Fun, Photos and Games
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What Determines the Motion of a Hockey Puck on a Frictionless Surface?
Their equation in #2 looks good. Using d=v*t for second piece.- Jakeus314
- Post #26
- Forum: Introductory Physics Homework Help
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What Determines the Motion of a Hockey Puck on a Frictionless Surface?
Correct. The puck does not stop moving.- Jakeus314
- Post #25
- Forum: Introductory Physics Homework Help
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What Determines the Motion of a Hockey Puck on a Frictionless Surface?
I can't say for sure why you got acceleration units. Do unit analysis to see what it should be, given the values you added or multiplied.- Jakeus314
- Post #20
- Forum: Introductory Physics Homework Help
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What Determines the Motion of a Hockey Puck on a Frictionless Surface?
Check my post 14 again. Do pt B by adding three things. Pt A answer, d=r*t during the 3 seconds of no acceleration, and last add the distance traveled while accelerating for 2 seconds with a starting velocity of ptA velocity.- Jakeus314
- Post #19
- Forum: Introductory Physics Homework Help
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What Determines the Motion of a Hockey Puck on a Frictionless Surface?
5^2 is an error here. Has the puck been accelerating for 5 seconds?- Jakeus314
- Post #18
- Forum: Introductory Physics Homework Help
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What Determines the Motion of a Hockey Puck on a Frictionless Surface?
Maybe I'm just being picky. When people say it that way I start thinking they're missing some algebra/units/equation concepts. Is English not your first language?- Jakeus314
- Post #17
- Forum: Introductory Physics Homework Help
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What Determines the Motion of a Hockey Puck on a Frictionless Surface?
The position in pt B comes from three distances traveled while moving. Pt A distance contributes some, then some more while moving at a constant speed, then more while accelerating again. Find the position for pt B from those pieces and you'll do fine.- Jakeus314
- Post #14
- Forum: Introductory Physics Homework Help
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What Determines the Motion of a Hockey Puck on a Frictionless Surface?
Good.. Because no force is acting on the puck from 2s to 5s.- Jakeus314
- Post #13
- Forum: Introductory Physics Homework Help
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What Determines the Motion of a Hockey Puck on a Frictionless Surface?
try not to say you converted an acceleration into a velocity... You may find a velocity using an acceleration etc. V = V0 + a*t V from pt A is good for V0 for pt B why?- Jakeus314
- Post #12
- Forum: Introductory Physics Homework Help
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Undergrad Can the merging of white dwarfs explain Type Ia supernovae explosions?
Type 1a is the result of a specific way a white dwarf reacts to gaining mass from another. Just don't assume that all white dwarf - white dwarf collisions result in 1a explosions.- Jakeus314
- Post #4
- Forum: Astronomy and Astrophysics
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What Determines the Motion of a Hockey Puck on a Frictionless Surface?
Should V initial at 5s be any different than V at 2s? Can you find V at 2s?- Jakeus314
- Post #8
- Forum: Introductory Physics Homework Help
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Does anyone else feel like it's all been studied already?
Just don't stop looking for new and meaningful questions. Even if it seems that they've all been asked.- Jakeus314
- Post #5
- Forum: STEM Career Guidance
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Can you simplify dimensional analysis for me?
A short and simple explanation? Break down the units of some quantities, cancel some units if possible, and make some kind of comparison of the units. Don't let the word dimensional scare you. Just think "do the units make sense?"- Jakeus314
- Post #3
- Forum: Introductory Physics Homework Help
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Undergrad I know the force of gravity inside a hollow sphere is 0, but
G dm1 m2 / r^2 to find net force. Or G dm / r^2 to find the field. Doing the integral with dm is a little odd feeling so write dm in terms of some coordinate system that makes symmetrical sense.