Can you simplify dimensional analysis for me?

AI Thread Summary
Dimensional analysis involves understanding the dimensions of physical quantities based on seven base units: time, length, mass, electric current, thermodynamic temperature, amount of substance, and luminous intensity. Each physical quantity can be expressed in terms of these dimensions, allowing for comparisons and conversions. Key rules include that only quantities with the same dimensions can be added or subtracted, and the dimensions of products or quotients are derived from the respective dimensions of the quantities involved. A practical approach to dimensional analysis is to break down units, cancel them when possible, and ensure that the units in equations make sense. This method simplifies complex problems and aids in verifying the correctness of physical formulas.
therealDR.DOG
Messages
4
Reaction score
0
Dimensional analysis...

I am having a real hard time wrapping my head around dimensional analysis. Can someone please explain it in english? Thanks.
 
Physics news on Phys.org


Every physical quantity f has dimensions ([f]) w.r.t. the seven base physical quantities:

  • time T
  • length L
  • mass M
  • electric current I
  • thermodynamic temperature \mathrm{\Theta}
  • amount of substance N
  • luminous intensity J

Luminous intensity is a photometric quantity. Its unit is the candela (cd). It is a subjective measure of how the human eye perceives light. If one is concerned with objective measures of radiation fluxes, then this unit is not used.

Amount of substance is directly proportional to the number of elementary entities in the ensemble. The unit is called a mole. The actual number of particles present in a mole of substance is considered a physical constant, although I would think that it makes more sense to call it a conversion factor. It is the Avogadro's constant:
<br /> N_A = 6.022 \times 10^{23} \, \mathrm{mol}^{-1}<br />

Similarly, due to developments in Statistical Physics, it had been shown that temperature is directly proportional to some energy ("thermal energy"). The unit of thermodynamic temperature is kelvin (K), whereas the unit of energy is joule (J). A conversion factor that converts any temperature (T) into energy units (\theta = k_B \, T) is the Boltzmann's constant:
<br /> k_B = 1.3806 \times 10^{-23} \, \frac{\mathrm{J}}{\mathrm{K}}<br />

The above two constants combine to give another famous constant - the Universal gas constant:
<br /> R = k_B \, N_A = 8.314 \, \frac{\mathrm{J}}{\mathrm{K} \cdot \mathrm{mol}}<br />

The unit of electric current is the ampere (A). If you look at its definition, it is defined through the force (a mechanical quantity) between two long straight conductors with given length, and a certain distance apart (both mechanical quantitites). Thus, there must be a conversion factor between mechanical quantities (time, length, and mass), and the electric quantitiy. Indeed, there is such a conversion factor, called the vacuum permeability:
<br /> \mu_0 = 4\pi \times 10^{-7} \, \frac{\mathrm{N}}{\mathrm{A}^2}<br />
Thus, in principle, all quantities have dimension only w.r.t. to the three mechanical base units:
<br /> [f] = \mathrm{T}^{\tau} \, \mathrm{L}^{\lambda} \, \mathrm{M}^{\mu}<br />
The exponents (the τ, λ, and μ, which are pure rational numbers) are the corresponding dimensions w.r.t. to each base quantity.

Some rules for dimensions are:
  • A dimensionless quantity has zero dimension w.r.t. each base physical quantity [f] = \mathrm{T}^0 \, \mathrm{L}^0 \, \mathrm{M}^0 = 1.
  • Both sides of an equality have the same dimension, i.e. f = g \Rightarrow [f] = [g]
  • You may only add (or subtract) quantities with the same dimension, i.e. h = f \pm g \Leftrightarrow [f] = [g] = [h].
  • The dimension of a product (quotient) of two physical quantites is he product of their respective dimensions, i.e. [f \cdot g] = [f] \cdot [g] (the exponents for each base quantity add (subtract).
  • A mathematical function (exp, log, sin, cos, etc.) accepts a dimensionless argument and returns a dimensionless result, i.e. y = f(x), \Rightarrow [x] = [y] = 1.
 
Last edited:
A short and simple explanation? Break down the units of some quantities, cancel some units if possible, and make some kind of comparison of the units. Don't let the word dimensional scare you. Just think "do the units make sense?"
 


Example:
Let us look at the following formula:
<br /> v = v_0 + a \, t<br />
according to the summation rule, we know that we must have:
<br /> [v] = [v_0] = [a \, t]<br />
Further, according to the product rule, we also have:
<br /> [a \, t] = [a] \cdot [t]<br />
Thus, if we want to express the dimension of a, we would have:
<br /> [a] = \frac{[v]}{[t]}<br />
 


its just weird because for kinematics I am having a way easier time then the majority of the homework in chapter one which involves a lot more than just changing units.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...

Similar threads

Back
Top