Recent content by jameo15

Oh ok that makes more sense. Now I find Wnet correct? Wnet= Wgrav ( answer from -1mgh formula) + Wp( answer from W=Fd formula)?

d=4m u=0.33 m=3.0x102N=30.6kg h=1.2m Ff=uFn=0.33 x 30.6 x 9.8= 98.96N Wgrav=-1mgh=-3(30.6)(9.8)(1.2)=359.9J W=Fd=98.96 x 4 W=3879.2J I do not believe this is right..

A girl pushes a 3.0x102N box along the floor for a distance of4.0m. The coeffifient ofkineticfriction is0.33. She then lifts the box straight up 1.2m. What is the total amount of work she has done? I converted 3.0x102N to kgs and found Ff. Then I found work. Then I found Wgrav. Now I am...

Would it's vertical speed be the acceleration due to gravity? But at the point where it leaves the surface, it should be zero right?

Physics 12 Kinematics Question.. Please Help! Homework Statement A ball rolls off the top of a 12.5m building with a speed of 3.4m/s. How long does it take to hit the ground? What is the range from the base of the building? Homework Equations V = V0 + at V2=V02 + 2ad Avg V = (V = V0)...