How Long Does a Ball Take to Hit the Ground from a 12.5m Building?

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Homework Help Overview

The discussion revolves around a kinematics problem involving a ball rolling off a 12.5m building with an initial speed of 3.4m/s. Participants are exploring how to determine the time it takes for the ball to hit the ground and the range from the base of the building.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand the vertical and horizontal components of motion. There is a question about the vertical speed of the ball at the moment it leaves the building and whether it is affected by gravity.

Discussion Status

Some guidance has been offered regarding the separation of horizontal and vertical motion. Participants are actively questioning the assumptions about initial vertical speed and acceleration due to gravity, indicating a productive exploration of the problem.

Contextual Notes

There is a mention of needing an angle to find the range, which suggests that the problem may involve additional considerations beyond the vertical drop. The original poster has expressed uncertainty about their calculations and the setup of the problem.

jameo15
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Physics 12 Kinematics Question.. Please Help!

Homework Statement


A ball rolls off the top of a 12.5m building with a speed of 3.4m/s. How long does it take to hit the ground? What is the range from the base of the building?


Homework Equations


V = V0 + at
V2=V02 + 2ad
Avg V = (V = V0) /2
d = V0 + 1/2 at2


The Attempt at a Solution


All I've got was a sketch drawn.. Please help me. Well I timed 12.5 by 3.4 to get how long it took to hit the ground but I'm not sure if it is right. I'm guessing to find the range you must need an angle of some sort?
 
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jameo15 said:

Homework Statement


A ball rolls off the top of a 12.5m building with a speed of 3.4m/s. How long does it take to hit the ground? What is the range from the base of the building?


Homework Equations


V = V0 + at
V2=V02 + 2ad
Avg V = (V = V0) /2
d = V0 + 1/2 at2


The Attempt at a Solution


All I've got was a sketch drawn.. Please help me. Well I timed 12.5 by 3.4 to get how long it took to hit the ground but I'm not sure if it is right. I'm guessing to find the range you must need an angle of some sort?
Welcome to PF jameo15,

You need to consider the horizontal and vertical components of motion separately. When the ball rolls off the building, just at the point where it leaves the surface, what is it's vertical speed?
 


Would it's vertical speed be the acceleration due to gravity? But at the point where it leaves the surface, it should be zero right?
 


jameo15 said:
Would it's vertical speed be the acceleration due to gravity?
No, but that would be it's acceleration.
jameo15 said:
But at the point where it leaves the surface, it should be zero right?
Correct. So using this information, can you determine how long it takes to hit the ground (just considering vertical motion).
 

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