Recent content by Jas014

I went lamda = hc / work function workfuntion = hc/lamda = 6.626 * 10 ^-34 ( 3 * 10 ^8) / 3.25 * 10 ^ -7 = 6. 11 * 10 - 19 Now I am not sure if i take that number and multiply it by 1.6 * 10 ^ -19?

Homework Statement The wavelength associated with the cut-off frequency, for silver is 325 nm. a) What is the work function for silver? b) Find the maximum kinetic energy and speed of the electrons ejected from a silver surface by ultraviolet light of wavelength 254nm Homework...

The wavelength associated with the cut-off frequency, for silver is 325 nm. a) What is the work function for silver? b) Find the maximum kinetic energy and speed of the electrons ejected from a silver surface by ultraviolet light of wavelength 254 nm. So far for part a) i have: f = c /...