I went
lamda = hc / work function
workfuntion = hc/lamda = 6.626 * 10 ^-34 ( 3 * 10 ^8) / 3.25 * 10 ^ -7 = 6. 11 * 10 - 19
Now I am not sure if i take that number and multiply it by 1.6 * 10 ^ -19?
Homework Statement
The wavelength associated with the cut-off frequency, for silver is 325 nm.
a) What is the work function for silver?
b) Find the maximum kinetic energy and speed of the electrons ejected from a silver surface by ultraviolet light of wavelength 254nm
Homework...
The wavelength associated with the cut-off frequency, for silver is 325 nm.
a) What is the work function for silver?
b) Find the maximum kinetic energy and speed of the electrons ejected from a silver surface by ultraviolet light of wavelength 254 nm.
So far for part a) i have:
f = c /...