Recent content by Jason03

No i see now...For some reason I wasnt seeing A as the pivot point...when I thought of the 800N downwards I was seeing it as going counterclockwise but that would not be true because point A is a pivot holding it in place causeing it to rotate clockwise...

perfect!...that makes sense...I thought it was something to do with mass not changing...but i forgot i was taking the derivative with respect ot time... thank you

I have a diagram below for the problem...what I am trying to understand is when the moments are found about point A as they are in the solution...the 800N force downward is considered positive and the Cy reaction is considered negative...and the Cx is considered positive... What confuses me...

I had a question on the first derivative of Kinetic Energy...This a problem from the FE exam... Now the solution is = mva...which turns out to be power...im just trying to understand how they came up with that... so KE = 1/2 mv^2 im asuming they are using the general power rule so v^2...

I am tyring to solve the follwing problem... http://www.imagedump.com/index.cgi?pick=get&tp=549226 What is the appropriate K valuefor this to be a legitimate probability density function? Im not exactly sure of the approach to this problem...

I thought the power factor was included in the 3600 watts since its the real power...and if its not resistive what is it?...Im just using the methods that are shown in my text...but the example I am going off of is in DC...

Here is my work below...let me know if it looks ok...the power loss is the power loss in the lines... http://i674.photobucket.com/albums/vv106/jason03_2009/hw2.jpg

ok so I used the formula P = VI* power factor...this allowed me to solve for I which gave me 30 amps... So I looked up the AWG chart and found that AWG No. 10 can have a max of 30 amps... So if that is correct...I now have to find the losses in the wire... What is the easiest way to...

any ideas?...I can understand a cell not functioning acting as a resistor...but why 5 ohms?

Ok...so I was looking at a few equations...could I use the equation for REAL POWER which is: P = VI cos(theta) because I have P...and I have V...and I can find cos(theta)... my only question would be since it 240 volts...im assuming that's in RMS already so I can just plug it straight...

The problem I am working on states that I have a power factor of .5, a real power of 3600 watts, a voltage of 240 V, and a distance between a motor and transformer of 100 feet. Im trying to find the Minimum wire gauge that could be used... Do I need to find the current and than go to...

Im working on a problem that involves a PV module consisting of 40 cells each at .5 volts. The problem models the module as having all 40 cells in series. The PV module is connected to a 5 ohm load. The problem also says to assume that the same current and voltage flows through the PV module...

Thanks!...Just checking to see if it was right...

good call...its 52 gallons.. but I did the correct conversion in my calculations...

Yea I am used to SI units as well...I just worked with the units given since the conversions were given...I guess I could try it the other way to if I did it correctly