Recent content by JaySean

  1. J

    How to Solve Pendulum Forces in Component Form?

    r(t)=(K*r)i-K*L0j would this be correct?
  2. J

    How to Solve Pendulum Forces in Component Form?

    So K(r-L0) works both in x and y direction? Am I then supposed to split the force and find which force works in x and y direction?
  3. J

    How to Solve Pendulum Forces in Component Form?

    Is mg=y component correct or is it wrong? And what force is working in the x direction? Or did I misunderstand what the task is asking for?
  4. J

    How to Solve Pendulum Forces in Component Form?

    Is it Hookes law? I assume we divide r vector by its magnitude to determine the direction of the force
  5. J

    How to Solve Pendulum Forces in Component Form?

    Homework Statement Hi, I need help in solving question c) (a pendulum) The required data, problem and relevant equation is in the pictureThe Attempt at a Solution I am not sure how to solve it but here are my thoughts: since mg is working at j y(t)j= mg does that mean K(r-L0) x(t) direction? I...
  6. J

    Finding Accel. of Particle: t1=2s t2=5s | Mean Accel.

    Do you mean derivating for example the formula v=v0+at?
  7. J

    Finding Accel. of Particle: t1=2s t2=5s | Mean Accel.

    Sorry this is stupid of me, (37,5-6)/3 =10,5 v1-v0/delta(t) I have another question not sure if anyone is able to answer: Car with velocity 36 km/h colliding and stoping over a length of 1 meter (end velocity = 0). Find acceleration. I have solved it the simple way using v^2 = u^2 + 2as and...
  8. J

    Finding Accel. of Particle: t1=2s t2=5s | Mean Accel.

    Since I already know what alpha is and time is I might be able to use the general formula for acceleration knowing the velocity at beginning and end. This gives me vo=3*(2)^2=12 v1=3*(5)^2=75 acceleration= (75-12)/(5-2)=21
  9. J

    Finding Accel. of Particle: t1=2s t2=5s | Mean Accel.

    Sorry I meant 21/3 m/s^2 which is 7m/s^2 a(2)+a(5) =6+15=21 And t2-t1=5-2=3
  10. J

    Finding Accel. of Particle: t1=2s t2=5s | Mean Accel.

    (I didn't know how to write alpha so I just called it q) So the formula for poisition as a function of time is S(t)=0 when t=0? and for b) since a(t)=qt where q=3 m/s^3 for t1= 2s and t2=5s a(2)=6 m/s^2 and a(5)=15 m/s^2 mean acceleration= 11/3 m/s^2
  11. J

    Finding Accel. of Particle: t1=2s t2=5s | Mean Accel.

    I know that the distance particle traveled is s(t)= antiderivative of v(t), but wouldn't I need additional information to find the constant? Edit: Already found the formula for acceleration a(t)= qt where q is a constant
  12. J

    Finding Accel. of Particle: t1=2s t2=5s | Mean Accel.

    Do I have to solve it as differintial equation? As I'm not allowed to use the formula for constant accerlation? I know I can derivate v'(t) to get a(t)= at where a= alpha, but how do get to the length formula?
  13. J

    Finding Accel. of Particle: t1=2s t2=5s | Mean Accel.

    There is no additional information, but the formula (picture). Do you have any hint to how I get started on solving b)?
  14. J

    Finding Accel. of Particle: t1=2s t2=5s | Mean Accel.

    1. Not sure if it's the right forum but I'll try. The velocity of an particle varies quadratic with a formula based on time a) Find the equation for acceleration and length as a function of time. b) a = 3 m/s^3 (I think it's alpha) Find the acceleration when t1=2s t2=5s and how big is the mean...