Recent content by jazzyfizzle

Oooh. That makes sense. Duh.

So I have the problem: A particle of mass m is at rest at t=0. A linearly increasing force F=bt is applied. Find the velocity and displacement of the particle at t=t1>0 What exactly is bt? Can it be set equal to ma?

v0 ---> (F0t0)/m t ----> 2 a -----> (2F0)/m

For the second segment I'm getting the distance as [F0(3t0 + t0^2)]/m

Ooh, well I never went back and added the first segment.. maybe that's where I went wrong ? .. and my algebra could be a little off too. I'll probably need to go back and double check that also.

The definition of acceleration is the change in velocity over the change in time

Ok what I did was : First I used x=v0t+1/2at^2 to find the distance traveled for the first segment before the force doubled I plugged in a=(F/m) for the acceleration and v0=0 for the initial velocity Then i got x=1/2(F0/m)t^2 for the first segment Then, i used vf^2=vi^2+2ax to find the...

For a final answer I got x=((2F0*t0^2)/m)) + (4F0t0)/m But... I don't think that's right at all...

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