Recent content by jefgreen
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Mirror/Lens Equation and Resistors in Parallel
Thank you guys for all of the help. I understand everything :).- jefgreen
- Post #12
- Forum: Introductory Physics Homework Help
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Mirror/Lens Equation and Resistors in Parallel
I apologize for my pathetic lack of basic math, but could you walk me through the process of how to get the answer?- jefgreen
- Post #9
- Forum: Introductory Physics Homework Help
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Mirror/Lens Equation and Resistors in Parallel
Bump10char- jefgreen
- Post #7
- Forum: Introductory Physics Homework Help
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Mirror/Lens Equation and Resistors in Parallel
36 would be the lowest common denominator. 1/36+1/36+1/36=3/36? 36/3=12 Correct?- jefgreen
- Post #6
- Forum: Introductory Physics Homework Help
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Mirror/Lens Equation and Resistors in Parallel
Bump10char.- jefgreen
- Post #3
- Forum: Introductory Physics Homework Help
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Mirror/Lens Equation and Resistors in Parallel
In addition, sometimes I am asked to solve for R2 (using the Parallel circuits equation) and do (using the mirror/lens equation).- jefgreen
- Post #2
- Forum: Introductory Physics Homework Help
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Mirror/Lens Equation and Resistors in Parallel
I'm not sure how to find the least common denominator when given these formulas:- jefgreen
- Thread
- Parallel Resistors
- Replies: 11
- Forum: Introductory Physics Homework Help
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Do I have to break these problems up into component vectors?
I'll try.- jefgreen
- Post #4
- Forum: Introductory Physics Homework Help
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Do I have to break these problems up into component vectors?
bump10char.- jefgreen
- Post #2
- Forum: Introductory Physics Homework Help
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Do I have to break these problems up into component vectors?
#8: A person walks 60.0 m east, then 80.0 m NW. #9: A person walks 15 m west, then walks 7.0 m @ 15 degrees South of West. #10: Two forces act on an object. A 45 N force pushing to the north, and a 70 N force pushing at 20 degrees to the east of north. #11: Some people go for a walk...- jefgreen
- Thread
- Break Component Vectors
- Replies: 5
- Forum: Introductory Physics Homework Help
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Solving Pressure: P = 7.35N / (.24m x .2m)
bump 10 char- jefgreen
- Post #5
- Forum: Introductory Physics Homework Help
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Solving Pressure: P = 7.35N / (.24m x .2m)
@RoyalCat: How should plug them in?- jefgreen
- Post #4
- Forum: Introductory Physics Homework Help
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Solving Pressure: P = 7.35N / (.24m x .2m)
bump 10 char- jefgreen
- Post #2
- Forum: Introductory Physics Homework Help
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Solving Pressure: P = 7.35N / (.24m x .2m)
1. Relevant equations P=F/A 2. The attempt at a solution P= 7.35 N ------------- (.24m)(.2m) Answer= 150.0 PA. <-- That is the correct answer which my instructor gave me. Although, whenever I plus this into my calculator I wind up with 6.125 or 6.16666... (when...- jefgreen
- Thread
- Pressure
- Replies: 5
- Forum: Introductory Physics Homework Help
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Pressure/Surface Area. Need to Find SA and Calc. Pressure.
Bump. Help please.- jefgreen
- Post #3
- Forum: Introductory Physics Homework Help