Recent content by jelly1500

oh ok, thank you for all your help!

Oh sorry for not making that clear: D and E are correlated, so the direction of the resultant force exerted by the car on the road.

Ok, thank you so much. And for part e, I would then get the inverse tan of 10486/2793.9? 10486 being the force of gravity in the y direction and 2793.9 being the resultant force in the x direction.

So would the forwards directing force be F=2150.7 (from answer a) and the backwards directed force coming from the trailer be T=643.2 (answer b), giving me a total resultant force of 2793.9. Sorry I'm still a confused.

[SOLVED] Resultant force on a car Homework Statement A 1070 kg car is pulling a 320 kg trailer. Together the car and trailer move forward with an acceleration of 2.01 m/s2. Ignore any frictional force of air drag on the car and all frictional forces on the trailer. Determine the following. (a)...

Ok, I'm still a little confused. So now I have set up one of my legs on my right triangle as 2 mi/hr for the direction of the water flow, and the other leg as 1.0 mile for the distance he covered. Then I solved for the resultant vector: square root of 2^2 + 1^2, which equals 2.24. Then I plugged...

oh, I get it! I'm supposed to break in down into it's x and y components. Thank you so much!

after the first 10 sec., its 250 meters away, then after the second 10 sec., its 750 meters

Homework Statement A person who can swim at 2.0 mi/hr is swimming perpendicularly to the bank of a river (directly across the direction of river flow) which is flowing at 2.0 mi/hr. If the river is 1.0 mi wide, how long does it take to reach the other side? Homework Equations t=x/v...

[SOLVED] acceleration and velocity 1. Homework Statement EXACT PROBLEM: A car accelerates from rest W at 5.0m/s2 for 10.0s, then continues this acceleration NE for another 10.0s. What is the average velocity of the car for its journey to its position after 20.0s? 2. Homework Equations average...