Recent content by Jessica Sweet

I'm thinking of W = Fdcosθ

Could someone demonstrate this? Because I'm a little lost.

I'm just curious, is there a way to find that without needing that equation??

Oh okay! I totally forgot about that equation. v2 = vi2 + 2a(delta x) That'll give me acceleration, and then I use F=ma, right?

Please help! I have a test tomorrow. 1. Homework Statement A car with a weight of 15,000 N moves horizontally at 30 m/s. a) What is the car's KE? b) What will be the magnitude friction force to stop the car over a 60m distance? Homework Equations F=ma KE=1/2*m*v2 The Attempt at a Solution a)...

Never mind, I got it all covered. My brain is working again. It's amazing what stress can do to the brain. Thanks for the help everybody.

Are you saying I could have subtracted the 160 from 360? What value does the 160 J represent that I solved for? Gosh, I feel stupid.

Alright, so Ftotal = 45 N, I am looking for frictional force, and ma = 20. 45-Ffk = 20 Ffk=25 Then I have Wfk = -(25)(8) = -200 J? Is this the correct answer?

Um, 45 N of force was applied to it. Would force of kinetic friction be -45 N then? Or am I just getting myself confused?

Homework Statement A person pulls a box (m=10 kg) horizontally with +2m/s2 acceleration by applying 45 N force. The displacement of the box is 8 meters from initial position. a) How much work is done by applied force? b) How much work is done by kinetic frictional force? Homework Equations Wf...