Recent content by jhmz

  1. J

    Sound attenuation barrier height (trigonometry)

    Homework Statement http://img543.imageshack.us/img543/4598/photosfr.jpg Find dss, dsr and thus hs. Homework Equations trig The Attempt at a Solution dss = hs/(sin[θ]) dsr = hs/(sin[∅]) dss = 3.059/(cos[θ]) dsr = 47.191/(cos[∅]) θ = arctan(hs/3.059) ∅ = arctan(hs/47.191) I have tried...
  2. J

    Stress Analysis - compound cylinders

    alll good figured it out
  3. J

    Stress Analysis - compound cylinders

    Homework Statement problem attached Homework Equations attached but lame equations i think they are? The Attempt at a Solution attached Hey this is an assignment question that i have wasted countless hours on trying to solve without success. The problem is WBVMMECH025 from the...
  4. J

    Engineering Pursuing a Masters in Engineering with a BA in physics?

    So I've just finished my first year of mechanical engineering in Australia (pretty generic subjects) and now is the time i need to make sure I am doing the right major. I've been quite sure throughout the year that mechanical is what I want to do however after doing my first unit of electrical...
  5. J

    Power Factor Correction: Calculating True and Apparent Power in a Circuit

    this might help: http://img516.imageshack.us/my.php?image=pfsd0.jpg im doing the same question and am in same situation as op My load impedence is 3 + j3 i started out using: \frac{1}{Z_{L}}=\frac{1}{Z_{C}}+\frac{1}{Z_{PL}} where Z_{PL}= Impedance of previous RL load which was 3+j3 and...
  6. J

    Partial Fraction Expansion with repeated roots

    That is quite creative and works out logically...just manipulating what is there, i would have never thought of that. Thanks for your help and will surely be keeping that advice in mind =)
  7. J

    Partial Fraction Expansion with repeated roots

    im trying to work out how to use partial fractions on a fraction with repeated roots. I am learning about laplace transforms at the moment, i don't remeber the lecturer specifically going through how to solve the transforms that have repeated roots and can't find it anywhere in the lecture...
  8. J

    Engineering Solving Dependent Voltage Sources in AC Circuit Mesh Analysis

    ok up until 5minutes after i posted this i thought that the dependent source was a voltage source (facepalm) i should have known it was a current source lol. So it makes things easier that it is a current source. Vo is simply I1 - I2, as V = IZ but the impedance at the resistor is 1 so...
  9. J

    Engineering Solving Dependent Voltage Sources in AC Circuit Mesh Analysis

    Im doing mesh analysis on an AC circuit only problem is i don't know how to handle the dependant voltage source. My circuit: http://img139.imageshack.us/my.php?image=accircuitrx0.jpg I think I am supposed to just assign a value for Vo but I am not sure. Is it possible to work out what Vo...
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