Recent content by ji707

I tried this not sure if its correct. i used this theorem ##(col A)^\perp = Nul A^T## since i was given ## A^T\vec{b} = \vec{0} ## ##Nul A^T = \vec{b}## and this means that ##\vec{b}## is already orthogonal to ##col A## and because ##\vec{b} - \hat{b} = \perp## to ## Col A## ##\hat{b} =...

hi all, i was given a take home exam for my linear algebra course and i can't seem to find the answer to this problem. Homework Statement if A^T\vec{b} = \vec{0} what can you say about ##\hat{b}## the vector in Col A which is the best approximation of ##\vec{b}##. Homework Equations ##A^T A...

ok, I am finding the theoretical x value so i did Mgh(point A)=1/2 Mv^2+1/5 Mv^2+Mgh(end of track) .913J= .0475v^2+ .019vt^2+ .484J v_exit=2.539 m/s Then i found the Y component 2.539*sin(3pi/4) = 1.79 m/s then into kinematic for a free falling object 0 =...

thank you tiny-tim. so i did the problem and found my x to be 1.43m does that seem right, i feel like I am way off...

Ill try to clarify, after all of this, they gave us an x value and told us to use that given value to find a new exit velocity corresponding to the new x value of the projectile, so when i tried to plug in the x displacement value they gave us i figured that since the exit velocity had...

How would i go about finding the exit velocity given an x value? ive tried plugging into the kinematic equations but i can't solve for both v and t...

ahh, thank you i was stuck on this for a while but knowing the loop cancels out helps a lot, thanks : D

1.hi, I am new to this forum and i have a question regarding my final physics lab: A solid spherical ball, R= 1.4 cm and m=95 grams, is released from point A(1m above the). After traveling through the loop, the ball exits the set up as a projectile and land at point B with the horizontal...