So we have an incline of slope θ, which is I circular motion around a pole with steady angular velocity ω. A body on the incline is at distance r frome the pole and stays at rest. Calculate the minimum friction coefficient so that it stays at rest.
So I analyzed the forces in 2 different...
The distance covered by the first box is :s1max=v²/2|a|=v²/2μg where a=-μg by second newtons law
Similarly S2max=(2v)²/2|a|=4v²/2μg
It gas to be s1max+s2max≥S => v²/2a +4v²/2a ≥s => 5v²≥2aS =>v²≥ 2μgS/5=> v≥√(2μgs/5)
But this is in the possible solution, am I wrong somewhere? I appreciate your help