Recent content by JMxBelfast

Homework Statement Need help at "Forming an equation based on the fact that all the vertical forces must be in equilibrium". I'm to calculate the reactions at the supports A and B by doing: (i) Forming an equation based on the fact that all the vertical forces must be in equilibrium (ii)...

I'll have a wee look into it, thanks again bud

Ah okay thanks a bunch, that's basically me done that whole question now, wouldn't have made it without you to be honest so thank you very much, and did you draw that diagram just to show me? If so I applaud your dedication to helping someone understand something :)

That's a good way to put it to be honest, I'm guessing 2.41m on the opposite side of the equilibrant? So basically what you said but dumbed-down for myself..

Do you think you could use you're great knowledge once again, to help me find the position of the resultant force, it asks in the question to find it and I'm not sure what to do. It also says in the question that "the weight of the tool can be assumed to act through its center" if that is relevant.

Ah yes fair enough, and is d the position of both the resultant and equilibrant force?

Okay thanks, and the units being..? Newton Meters?

The equilibrium's y-component? The resultant's y-component was -9.26kN so should the equilibrium's y-component be 9.26kN, since it's in the opposite direction? M = (-8.66x0) + (-10.6x4) + (-5x2) + (15x2) + (9.26xd) = 0 And then, (-8.66x0) + (-10.6x4) + (-5x2) + (15x2) = -22.4kNm -22.4 x -1 =...

Ah okay, so can I add the equilibrant force to the sum like this: M = (-8.66x0) - (-10.6x4) - (-5x2) - (15x2) - (10.8xd) = 0 And then, (-8.66x0) - (-10.6x4) - (-5x2) - (15x2) = 22.4 (I'm not sure if this is to be kN or Nm) 22.4 - 10.8d d = 22.4 / 10.8 d = 2 (Nm?) Sorry for not getting...

Honestly, nope hahaha, do I divide it by the equilibrium magnitude? I don't have my notes with me at the moment so I can't remember what I wrote down :rolleyes:

Okay thanks for the help again, I re-wrote the equation to try and fit what you said: M = (-8.66x0)-(-10.6x4)-(-5x2)-(15x2) = 22.4 Should I include F1 even though it has no effect on the moment? I removed it from the equation and done it again and got a different answer (-62.4) although I...

Okay, I'm back, yes I know so soon but I brought answers with me nonetheless, I came here to check them with your great knowledge or if it happens to be, someone else's great knowledge. So where did we leave off.. ah yes, the moments. Question 'iv' asked, "Find the position of the resultant and...

Alright well, I'll try and have a go at the moments question, thank you so much for the help, you don't understand how grateful I am ahahaha, I was fretting over it a lot and you managed to clear things up for me, I'll no doubt be back though.. but thanks again :smile:

Would they be.. Ex = -5.6kN and Ey = 9.32kN ?

121°.. I most definitely misclicked.. I added the two numbers together.