Recent content by Joe3502

  1. Joe3502

    Buoyancy with the Cross-Sectional Area of a Rectangle

    Thank you guys so much for helping me with this problem! I really appreciate it!
  2. Joe3502

    Buoyancy with the Cross-Sectional Area of a Rectangle

    Ahhhhhhh thank you for catching my mistake. Ok, so with that in mind: Fb = 3m^3 * 1000kg/m^3 * 9.81m/s^2 Fb = 2.94 x 10^4 N?
  3. Joe3502

    Buoyancy with the Cross-Sectional Area of a Rectangle

    How so?
  4. Joe3502

    Buoyancy with the Cross-Sectional Area of a Rectangle

    In that case, then 6m^2 * 0.5m = 3m^3 of water displaced.
  5. Joe3502

    Buoyancy with the Cross-Sectional Area of a Rectangle

    Fb = Vs*D*g So if that is the case, then: Fb = 0.5m * 1000kg/m^3 * 9.81m/s^2 Fb = 4905?
  6. Joe3502

    Buoyancy with the Cross-Sectional Area of a Rectangle

    Hi all, My teacher assigned us a problem to do a few days ago and have attempted it many times, often leaving and coming back to see if I could figure it out. I imagine that you would take the cross-sectional area and multiply it by how far under the surface of the water the rectangular object...