Recent content by johnsobertstamos
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Finding the Solution: Solving for x in a Polarization of Light Equation
Yep 36, thank you everybody for your help. Much appreciated!- johnsobertstamos
- Post #18
- Forum: Introductory Physics Homework Help
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Finding the Solution: Solving for x in a Polarization of Light Equation
Ah so maybe it's 36 then- johnsobertstamos
- Post #16
- Forum: Introductory Physics Homework Help
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Finding the Solution: Solving for x in a Polarization of Light Equation
I'm inputting x = log(2/9) / log((cos 12)^2) x = 34.037- johnsobertstamos
- Post #13
- Forum: Introductory Physics Homework Help
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Finding the Solution: Solving for x in a Polarization of Light Equation
It gets me the same answer of 34.037 Any differences in the equations we have set up?- johnsobertstamos
- Post #12
- Forum: Introductory Physics Homework Help
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Finding the Solution: Solving for x in a Polarization of Light Equation
Still at a complete loss for what I'm doing wrong here. My math checks out every time.- johnsobertstamos
- Post #10
- Forum: Introductory Physics Homework Help
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Finding the Solution: Solving for x in a Polarization of Light Equation
1) .5((cos 12)^2)^x = 1/9 2) ((cos 12)^2)^x = 2/9 3) x ln((cos 12)^2) = ln (2/9) 4) x = (ln (2/9)) / ln((cos 12)^2) 5) x = 34.037- johnsobertstamos
- Post #9
- Forum: Introductory Physics Homework Help
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Finding the Solution: Solving for x in a Polarization of Light Equation
That's the phrasing given in the problem. I also forgot to mention it asks for the answer in the form of an integer.- johnsobertstamos
- Post #8
- Forum: Introductory Physics Homework Help
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Finding the Solution: Solving for x in a Polarization of Light Equation
The bottom one applies to just the first, reducing the intensity by half. The top one applies to the rest of the polarization stages.- johnsobertstamos
- Post #4
- Forum: Introductory Physics Homework Help
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Finding the Solution: Solving for x in a Polarization of Light Equation
Sorry, should be 1/9- johnsobertstamos
- Post #3
- Forum: Introductory Physics Homework Help
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Finding the Solution: Solving for x in a Polarization of Light Equation
I set up the equation .5((cos 12)^2)^x = 1/9 Solving for x gets me 34.037 34 + 1 = 35 I've entered answers of both 34 and 35 and both have been marked as wrong. Does anybody know what I'm doing wrong here?- johnsobertstamos
- Thread
- Light Polarization
- Replies: 17
- Forum: Introductory Physics Homework Help