Recent content by Johnyi

Im not sure what you mean by this. Can you explain more please

Homework Statement The reaction below has a equilibrium constant of Kp = 2.26 x 10^4 at 298 K CO(g) + 2H2(g) <=>CH3OH(g) Calculate Kp for each of the reactions and predict whether reactants or products will be favored at equilibrium A. (1/2)CO(g) + H2(g) <=> (1/2)CH3OH(g) Homework...

Im sorry i don't understand

I thinking that you can factor out a e^(2x). So it would be e^(2x)(x+1). Then subtract 1 to the other side, then divide by...I have no clue

Im sorry i just can't seem to do this right..so far i got x(2e^(2x))+e^(2x) =2e^(2x)x+e^(2x)

So i get 2xe^(2x) = 0 The answers in the back of the book say that x = 1/2 but i just can't seem to find a way to that answer

Homework Statement Let f(x) = xe^(2x) A) Find the values of x for which the slope of the cruve y = f(x) is 0 B) Explain the meaning of your answer to part (a) in terms of the graph f Homework Equations The Attempt at a Solution I tried setting xe^(2x) to 0 by making it 0 =...

So then wouldn't they both cancel anyways leaving me with just (x+4)?

Sorry..I just can't understand how the "-" sign came out of nowhere, and why i have to rewrite the denominator as -(x-4)

So if i distribute the - it will be -x+4, which cancels with the denominator, and I am left with x+4. I plug in 4 for x and get 8?

Where did you get the - before the (x-4) though?

Wouldnt that just be 0? Also why is there a - before the (x-4)?

Homework Statement Lim x^2-16/4-x x→4 Homework Equations The Attempt at a Solution I factored it, and ended up with (x-4)(x+4)/(4-x) Cant cancel anything out, so I plug in 4 back into it, and end up with 8 as the limit. But the book says that the...

How do i get the opposite value?

My solution: b^2=(x^2+16/16) + 1 I don't know what to do from there!