Recent content by jonney

Hey thanks heaps for that, just one more question how do i know that this line is parallel to the vector. I got x = (0,0,0)+t(9,6,0) for the vector equation of the line does this look right. also sorry about the confusion on the (960) when it should have been (9,6,0).

here is what i have come up with is this right general equation for line 1 x-y+z=0, parametric equation x=s y=2s z=s general equation for line 2 x+y+z=15, parametric equation x=9 y=6+t z=-t then created a line with the vector (1,-1,1) going through the origin. x =(0,0,0) +v(1,-1,1)...

given two lines x=s(1,2,1) and x=(960)+t(0,1,-1) how would i go about finding a vector that intersects both lines and then finding another line parallel to that vector? help would be much appreciated