But if we just assume for now that the line will hold and the mans feet won't get wet, will 1000 kg on each side hold the line and the man walking on it?
I'm thinking, is it reasonable to assume that the line stretches linearly? Isn't most of the stretch taken out in the beginning? Is it possible to define the stretch with a function that increases a lot in the beginning but less after some time, like ln(x)?
If we say that the mans feet are...
If we assume that the man stands in the middle when he jumps the length of the line needs to be
2\sqrt{6^2 + (0.5)2}= 12.04 cm
So the line can only stretch 4 cm more so that the man won't touch the water.
Like you said we took 20 cm of the stretch away when we stretched the line up to 5 kN...
This is a problem I were given, but not for school.
We are going to set up a slackline like this and we were wondering if a tank with 1000 l of water on each side will hold the line or will it slide on wet anti slip tiles.
Is 1000 or each side enough or do we need more?
Thank you for you...
I'm sorry, I am really bad in this friction business, how would you define the friction for this sort of setup?
The setup is supposed to be like this I think
http://www.slacklining.ca/wp-content/uploads/2012/02/Waterlining21.jpg
except that on ether side there is a box lifts the line...
Thank you for the reply, I'll clear those thins up a bit.
The line stretches 5% under maximum tension, that it will hold, that is 15 kN, so it will stretch a bit more when the man walks on it.
By box I meant all sides equally long (50cm) (English is not my first language) so they are in the...
Homework Statement
A 12 m long line, that streaches 5% of its length is streched in 0.5 m hight over water.
The force that is used to keep the line streced is 5kN (kilo Newtons).
if an 90 kg man walks out the line and jumps up one meter and lands back on the line,
How heavy does the load...