Recent content by jpc90
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Calculating Distance Change of Plane from Radar Station
1.5dy/dt + 2.5dx/dt= 2dr/dt 1.5(0) +2.5dx/dt= 2(-400) 2.5(dx/dt)=-800 dx/dt= -800/2.5 = -320 ?- jpc90
- Post #8
- Forum: Calculus and Beyond Homework Help
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Calculating Distance Change of Plane from Radar Station
ok, so the distance is; 2.5^2= 1.5^2 + D^2 d=2- jpc90
- Post #6
- Forum: Calculus and Beyond Homework Help
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Calculating Distance Change of Plane from Radar Station
Its a triangle, and i got the distance as 2.915? If that's right, I still don't know what to do from there- jpc90
- Post #3
- Forum: Calculus and Beyond Homework Help
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Calculating Distance Change of Plane from Radar Station
Q) a plane is flying horizontally at an altitude of 1.5 miles and a speed of 400 mph. it is on a linear path that will take it directly over a radar station. find the rate at which the distance from the plane to the radar station is changing when the plane is exactly 2.5 miles from the station...- jpc90
- Thread
- Change Plane Radar
- Replies: 9
- Forum: Calculus and Beyond Homework Help
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Differentiate f(x)=arctan(e^5x)
ok thanks guys- jpc90
- Post #7
- Forum: Calculus and Beyond Homework Help
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Differentiate f(x)=arctan(e^5x)
I thought since e^5x is in the denominator that it is equal to e^-5x- jpc90
- Post #5
- Forum: Calculus and Beyond Homework Help
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Differentiate f(x)=arctan(e^5x)
I did something like, 1/1+(e^5x)^2 and then 5e^-5x/1+(e^10x) I don't think that is right though, I'm pretty confused- jpc90
- Post #3
- Forum: Calculus and Beyond Homework Help
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Differentiate f(x)=arctan(e^5x)
How do you differentiate f(x)=arctan(e^5x)- jpc90
- Thread
- Differentiate
- Replies: 6
- Forum: Calculus and Beyond Homework Help