Recent content by jpdelavin

@Poley: Is this what you mean? For particle 4 for example: .5*m4*v4^2=q*(kq/a+kq/a+kq/(a*sqrt(2))

momentum, perhaps? but that still would just leave me with two equations right, and i have four unknowns?

Homework Statement A square of side s has a point charge at each corner. They all have the same charge +q, but different masses, m1, m2, m3, and m4, respectively. Initially, all of the charges are held at rest until they are released. Of course, they would repel each other and move away from...