Recent content by jrodmckis

nevermind i figured it out. m=-1/tau and the slope is given

Given: slope of the graph of ln(temperature dimensionless) vs. time slope=-0.0416 -t/tau = ln(temperature dimensionless) I don't know where to put the slope into the equations? I know that the time constant is the tau. Also have -1/tau equation. I tried this...