Calculating Time Constant Using Slope of ln(Temperature Dimensionless) vs. Time

[jrodmckis]

Given:

slope of the graph of ln(temperature dimensionless) vs. time

slope=-0.0416

-t/tau = ln(temperature dimensionless)

I don't know where to put the slope into the equations?

I know that the time constant is the tau.

Also have -1/tau equation.

I tried this:

-(1/0.0416) = 24.04 sec is this the time constant?

 

[jrodmckis]

nevermind i figured it out.

m=-1/tau

and the slope is given

 

[berkeman]

Moved from General Physics to homework forums.