Recent content by Jufa
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Recommendation for a platform for drawing computational circuits
Thank you very much!- Jufa
- Post #3
- Forum: Electrical Engineering
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Recommendation for a platform for drawing computational circuits
Homework Statement:: I need to draw circuits involving quantum gates and quantum states I would like a platform that allowed me to draw quantum computation circuits. That is, that it provides me with the schemes and allows me to write in latex. Many thanks in advance.- Jufa
- Thread
- Circuits Computational Drawing Platform Recommendation
- Replies: 2
- Forum: Electrical Engineering
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A Eigenvalue of the sum of two non-orthogonal (in general) ket-bras
Yes. Namely between ##\ket{\psi}## and ##\ket{\psi^\perp}##. These are the two vectors involved. I reckon I am stating the problem in a clear way.- Jufa
- Post #13
- Forum: Linear and Abstract Algebra
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A Eigenvalue of the sum of two non-orthogonal (in general) ket-bras
Just an orthogonal vector.- Jufa
- Post #11
- Forum: Linear and Abstract Algebra
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A Eigenvalue of the sum of two non-orthogonal (in general) ket-bras
I maybe should have mentioned that both ket vectors belong to ##\mathcal{C}^2## and thus the perpendicular vectors are well defined up to a global phase. My attempt is the following: In the basis ## \ket{\psi}, \ket{\varphi}## the matrix looks like a diagonal one, namely: ##M = Diag\Big(...- Jufa
- Post #9
- Forum: Linear and Abstract Algebra
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A Tensor product matrices order relation
We mainly have to prove that this quantity## \bra{\varphi} A^{\otimes n } \ket{\varphi} \pm \bra{\varphi} B^{\otimes n } \ket{\varphi} ## is greater or equal than zero for all ##\ket{\varphi}##. Being ##\ket{\varphi}## a product state it is straightforward to demonstrate such inequality. I am...- Jufa
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- Matrices Product Relation Tensor Tensor product
- Replies: 1
- Forum: Linear and Abstract Algebra
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A Eigenvalue of the sum of two non-orthogonal (in general) ket-bras
Oh yes. You are definitely right, I am sorry for my confusion. I will work on your idea then. Thank you very much.- Jufa
- Post #7
- Forum: Linear and Abstract Algebra
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A Eigenvalue of the sum of two non-orthogonal (in general) ket-bras
I guess when you say ##\ket{\phi}## you mean ##\ket{\varphi}##. I don't think it makes sense to compute the entries of the matrix in a non-orthonormal basis. I don't think the associated characteristic equation has nothing to do with the one you get when an orthonormal basis is considered.- Jufa
- Post #4
- Forum: Linear and Abstract Algebra
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A Eigenvalue of the sum of two non-orthogonal (in general) ket-bras
We have a matrix ##M = \ket{\psi^{\perp}}\bra{\psi^{\perp}} + \ket{\varphi^{\perp}}\bra{\varphi^{\perp}}## The claim is that the eigenvalues of such a matrix are ##\lambda_{\pm}= 1\pm |\bra{\psi}\ket{\varphi}|## Can someone proof this claim? I have been told it is self-evident but I've been...- Jufa
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- Eigenvalue General Sum
- Replies: 13
- Forum: Linear and Abstract Algebra
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Preparing for a Quantum Computation Course: Superconducting Qubits
Yes. I will do so as well, but I am trying to find more literature.- Jufa
- Post #3
- Forum: STEM Academic Advising
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Preparing for a Quantum Computation Course: Superconducting Qubits
Summary:: Looking for articles/books to prepare myself for the course: Quantum computation with superconducting qubits Hello everyone. I am about to take a course in Quantum computation with superconducting qubits and I am searching for material to prepare it. I took a first course on that...- Jufa
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- Computation Course Quantum Quantum computation Qubits Superconducting
- Replies: 3
- Forum: STEM Academic Advising
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Why Shift ##z_0## by ##-i\epsilon## in Non-Convergent Integrals?
I am asked to compute ##[\phi(x), \phi^\dagger(y)]## , with ##\phi = \int \frac{dp^3}{(2\pi)^3}e^{-ipx}\hat{a}(\vec{p})## and with z=x-y a spacelike vector. And show that this commutator does not vanish, which means that for this non-relativsitic field i.e. with ##p^0 = \frac{\vec{p}^2}{2m}##...- Jufa
- Thread
- Integral
- Replies: 1
- Forum: Advanced Physics Homework Help
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Linear momentum of the Klein Gordon field
Yes. it is definitely not right. There's a two at the denominator missing and also the momentum p should multiply the whole expression. Thank you very much for your answer, what you told me about the expression being odd rescues everything.- Jufa
- Post #3
- Forum: Advanced Physics Homework Help
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Linear momentum of the Klein Gordon field
The correct answer is: #P = \int \frac{dp^3}{(2\pi)^3}\frac{1}{2E_{\vec{p}} \big(a a^{\dagger} + a^{\dagger}a\big)# But I get terms which are proportional to ##aa## and ##a^{\dagger}a^{\dagger}## I hereunder display the procedure I followed: First: ##\phi = \int...- Jufa
- Thread
- Field Klein Klein gordon field Linear Linear momentum Momentum
- Replies: 2
- Forum: Advanced Physics Homework Help
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A Concept of wavefunction and particle within Quantum Field Theory
Many thanks for your answer, it helped me a lot! Also I checked your paper and found it really interesting.- Jufa
- Post #3
- Forum: Quantum Physics