Yes, it would be counted twice. All root possibilities for any given polynomial would be a unique combination, and there is no rule saying that number can't repeat or anything either.
Thanks, I'm going to think about this and see what I come up with.
Not necessarily, more so the permutations where all coefficients, the x variable, and constant term are considered and all some combination between -100 and 100 such that, the combination satisfies the RS to equal 0.
I'm trying to imagine a 6D surface: ax³ + bx² + cx + d = y ... It would...
Sorry if this is the wrong thread, seems appropriate but I'm kind of just learning math. This started as a thought experiment to learn some new technique. I've been trying to compute the total number of integer polynomials under certain restrictions: such that all coefficients, x, and the...
:smile:I forgot to square the Planck constant and wavelength when working with the units alone... Were all good, thanks for the tip, I thought it might be easier to think about working with the units without numbers but I forgot about the powers of the value to begin.. I certainly see the...
I'm not sure if you can see where I'm going wrong in my units, I've tried using Plancks constant with J/s too but its also not Volts, although I know it is, but where am I going wrong.
I might be doing something wrong here, I tried this a couple of ways but I don't exactly line up with \frac{kg⋅m^2}{A⋅s^3}
I end up with this
\frac{m}{A⋅s^2}
But why the heck does the equation render a value within the realm of the centi-volt? I pull 15078.5 from the equation but I'm not sure the units,
and if you say its 150 volts, I'm in a new place of confusion.
...and wait, isn't electric potential diff in eV.. I jump at the conclusion due to the ΔV symbol and as eV's seem to be standard in this study? ... Thanks for pointing that out.
I was looking at this and my second algebra is terrible... I meant to write this but I was awake for way too long.Since λ= \frac{h}{\sqrt{2⋅m⋅E}} → E= \frac{h^2}{2⋅m⋅λ^2}
ΔV = \frac{E}{e} = \frac{(\frac{h^2}{2⋅m⋅λ^2})}{e} = \frac{h^2}{2⋅m⋅e⋅λ^2}