Recent content by JumpZero

Hello, Thanks for your answers. This is correct. I found it also (with help) with another method and result are the same: I1=15A I2=15A I3=26A This method: Phase currents = I=P/E, = O amps for L1-L2 (ab) 3300/220 = 15A for L2-L3 (bc) & 15A for L3-L1 (ac) Line currents = L1 =√(ab²+ac²)+(ab x...

Hello, I cannot find back from school, the formula to use: A 3 phases 220Vac system, no neutral, 3300W of pure resistance load between L2 and L3, the same load between L1 and L3, nothing between L1 and L2. What will be I1, I2, I3 the current in the 3 lines of the network? Thanks in advance -- Jmp0