Recent content by jweica

Ohhhhh okay that makes more sense! Thank you so much for clarifying this for me!

Given that the tibia is 0.6kg and is 35 cm long. The force at the knee (Fk) is: (-200i + 346.41j)N Find the moment about the ankle due to Fk I found that: r: rx = (0.35cos60) and ry = (0.35sin60) Using the sum of moments where: rxFy - ryFx = 0 [(0.35cos60)(346.41)] - [(0.35sin60)(-200)] =...

The problem has parts to it, and I'm supposed to find the diver's weight in the second part of this problem I figured that gravity is a downwards force, but the weight was the diver is unknown. Since the first part of the problem asked to find the force of board due weight of the diver...

Hello! I have attached a screenshot of my poor illustrated free body diagram. From the FBD, support 1 is acting downwards so it would be -5400N, and support 2 is acting upwards, therefore, in the positive direction... so 6000N. Overall, the person's weight (I'm assuming) wouldn't put out as...

The board is 4m and has 2 supports: support 1 exerts 5400N and support 2 exerts 6000N before the diver performs the dive. Neglecting the mass of the board, what is the force on the board due to the weight of the diver? My attempt at this question: FS2 - FS1 = 6000 - 5400 = 600N But I'm having...