Recent content by jxj
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Isolating Variable in Equation for conservation of momentum
for that part, was I supposed to separate them so I would have mA(vA) -(mA)(v’A) ?- jxj
- Post #16
- Forum: Introductory Physics Homework Help
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Isolating Variable in Equation for conservation of momentum
so right now I am at distributing mA by itself into (vA - mAv’A) on the left of the equal sign and vice versa for mB on the right of the equal sign. am I on the right track?- jxj
- Post #14
- Forum: Introductory Physics Homework Help
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Isolating Variable in Equation for conservation of momentum
thanks!- jxj
- Post #13
- Forum: Introductory Physics Homework Help
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Isolating Variable in Equation for conservation of momentum
when you say factorise could you explain a little more please- jxj
- Post #11
- Forum: Introductory Physics Homework Help
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Isolating Variable in Equation for conservation of momentum
I tried putting all of mA on the left and I got to mAvA - mAvA (prime) = mBvB (prime) - mBvB did I mess up?- jxj
- Post #8
- Forum: Introductory Physics Homework Help
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Isolating Variable in Equation for conservation of momentum
ok so right now I am a little confused because unlike the example you gave with 5x, the formula is essentially equal on both sides minus the primes. in my mind I would try to cross out the mAvA on the right, is that right?- jxj
- Post #7
- Forum: Introductory Physics Homework Help
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Isolating Variable in Equation for conservation of momentum
ok thanks- jxj
- Post #5
- Forum: Introductory Physics Homework Help
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Isolating Variable in Equation for conservation of momentum
when doing this, don't you divide the ##m_\mathrm{A}## plus ##v_\mathrm{A}## prime on the right by its counterpart on the left first? even though it contains a prime?- jxj
- Post #4
- Forum: Introductory Physics Homework Help
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Isolating Variable in Equation for conservation of momentum
Homework Statement So the problem is trying to isolate mA in the equation for momentum (only focusing on top formula, not bottom hehe) basically by solving the equation I assume. My teacher said because the vA and vB on the right were prime they could not be combined so I'm having trouble...- jxj
- Thread
- Conservation Conservation of momentum Momentum Variable
- Replies: 16
- Forum: Introductory Physics Homework Help
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Help with proportionality and literal equations
Lol I got it finally. it took some time to figure out directly and inversely proportionality.- jxj
- Post #17
- Forum: Introductory Physics Homework Help
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Help with proportionality and literal equations
thanks! I think that for C, if K is decreased by a factor of three and X is quadrupled, F would also decrease and quadruple? or does two changes change the proportionality? and for D. How do suppose I use the method of Literal Equations to isolate the spring constant and determine the units...- jxj
- Post #15
- Forum: Introductory Physics Homework Help
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Help with proportionality and literal equations
Yes, I tried the process as I used for A. and now I am wondering won't F decrease by a factor of 5, if x is decreased by a factor of 5?- jxj
- Post #13
- Forum: Introductory Physics Homework Help
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Help with proportionality and literal equations
Looking at B-C Seeing as how it uses X now, would it still be directly proportional to F or now jointly? I would have said X being decreased by a factor of five would result in F being decreased being by 5, though i’m unsure if that’s correct. also thanks for the explanation- jxj
- Post #11
- Forum: Introductory Physics Homework Help
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Help with proportionality and literal equations
thanks. seeing it shown as (x,y) made it somewhat easier to understand- jxj
- Post #10
- Forum: Introductory Physics Homework Help
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Help with proportionality and literal equations
you would essentially have -3kx/-kx, right?- jxj
- Post #6
- Forum: Introductory Physics Homework Help