Recent content by K3nt70

That's def. enough to get me started - i'll see where it gets me. thanks

Homework Statement 5) For each of the series below, write the series in summation notation and give the first five terms of the series. Also give the radius of convergence of the series. a) Use the series for \frac{1}{1 - x} to find the Maclaurin series of f(x) = \frac{1}{(1-2x)^3}...

Homework Statement A generator is constructed by rotating a coil of N turns in a magnetic field B at a frequency f. The internal resistance of the coil is R and the cross sectional area of the coil is A. Which of the following statements are true? (Give ALL correct answers, i.e., B, AC...

Correct! Thanks

jeez, why didnt i see that?:P So you would put your money on CDEF? i only have one attempt left at the question

any insight into this one?

Homework Statement The figures below show two different situations where a current may be induced in a loop according to Faraday's Law, with the direction given by Lenz' Law. The magnetic field is shown by the x's in Fig. 2. Select ALL correct answers (i.e. B, AC, BCD) for the current in the...

(x^2 + y^2) * \sqrt{x^2 + y^2} = x^2 \sqrt{x^2 + y^2} + y^2 \sqrt{x^2 + y^2}

I'm having trouble completing the integral. I get this far: dE_x = \frac{\lambda x}{4 \pi \epsilon (x^2 + y^2)} dx

and r(x) = \sqrt{x^2 + y^2} right?

Wouldnt it make sense to use Sin \theta ? Anyway these are the expressions i got for sin and cos: Cos \theta = \frac{x}{\sqrt{x^2 + y^2}} Sin \theta = \frac{y}{\sqrt{x^2 + y^2}} So.. i need to take the integral of: dE_x = \frac{x}{\sqrt{x^2 + y^2}}* \frac{\lambda dx}{4...

nevermind. I checked my answers with the formual for magnetic field, and it was correct.

edit: actially, i found d to be 1.50967 and the point on the x-axis to be -3.3096 cm. This makes sense, but I am kind of afraid to try it since i only have one more attempt at the problem. Any confirmations?

Homework Statement Consider two parallel conducting wires along the direction of the z axis as shown below. Wire 1 crosses the x-axis at x = -1.80 cm and carries a current of 2.60 A out of the xy-plane of the page. Wire 2 (right) crosses the x-axis at x = 1.80 cm and carries a current of 8.80...

Ok. You said that dEy was Cos\thetadE, right? and that dE = \frac{\lambda dx}{4 \pi \varepsilon r(x)^2} Meaning i have to perform the integral of: dE = Cos\theta \frac{\lambda dx}{4 \pi \varepsilon r(x)^2} I the theta i will be using is shown in...