Recent content by kajzlik

Well, not that difficult... Thank you, it really helped.

Thanks for your response. The formulation of my problem was quite confusing. First condition is ok, its just straight forward process that leads to sine function, but I'm completely lost with the second one.As you said it's obvious that second condition will hold for any "multiplying" constant...

Hello guys, suppose we have an eigenvalue problem \left\{ \begin{array}{ll} u'' + λu = 0, \quad x \in (0,\pi) \\ u(0)=0 \quad \\ \left( \int_0^\pi \! {(u^+)}^2 \, \mathrm{d}x \right)^{\frac{1}{2}} = \left( \int_0^\pi \! {(u^-)}^4 \, \mathrm{d}x \right)^\frac...