Recent content by KeevKK

This is the end result. Anyone care to confirm? :)

Got this instead after correction:

You are correct. I made a mistake. But was my approach correct?

Thanks a lot for your help! I have tried this: What do you think?

I intented to isolate a in the equation. To find the center of curvature when t=0.9 I have done the following so far: Then I found the velocity to be 15,431. But is that my tangential acceleration as well? I know the acceleration is 9.8m/s^2 but I am unsure what to do next.

Yet another question: What if I want to find the center of curvature?? My thoughts are these: First use the formula Vf=Vi+a*t to find the tangential acceleration. Then use this formula a^2=an^2+at^2 to find an which I will then use in the formula an=(v^2)/r in order to find r. Is this the...

I have a additional question for this problem. How do I derive a function for the curve when only Vinitial=10m/s is known? Edit: Never mind, I solved it!:)

What numbers did you use? But I think I got it: I still get 20,15m/s Thanks a lot!

Thank you! So you are saying that 20,15m/s is correct? English is not my first language so I find it a little difficult to understand what you are saying. When you say horizontal and vertical components you mean Vx and Vy right? And not Vxo and Vyo? I am a little confused of how to go about...

Okay sure. These are my attempts: In the first attempt i would know at what time the skier is 45 degrees and then I would put into the Vy equation, but it does not make sense to me since the movement is 1,6 seconds. That is why I did the second attempt. But I am not sure if this is correct...

Homework Statement The skier leaves with 10 m/s What is the final velocity parallel to the track when it is hit? Homework Equations The Attempt at a Solution I have already found out d which is 21,27m and the time for the movement which is 1.6s. I can also find the impact velocity, but how am...