Recent content by Kevin Shen

Yeah I realized I made the error and I get it now :)

Why is the equation Power Loss = I^2*R rather than Power Loss = V*I? What I mean is why use I/R to represent V? Also if Power Loss is equivalent to V*R, doesn't step up transformers which creating higher voltage also cause Power Loss to increase which contradicts to textbooks stating that power...

Thanks again, but how do you calculate the contact surface area and know why it decreases?

Sorry, I don't understand what you mean by that :(

What I mean is that in a given volume like in a tire, when there is higher temperature due to P1/T1 = P2/T2, there will be higher pressure. And the higher pressure is caused by the larger momentum change when particles interact with the wall so that they create a higher force over the area. And...

F is force

No..I'm not very familiar with this equation, but I thought that A stays the same due to P=F/A, and so due to higher kinetic energy causing an increased force and pressure, P and F will rise proportionally so F1/P1=F2/P2 and the area is left unchanged... Is this not right?

Hello! I am a high school student who is interested in physics and maths! The reason I joined the forum is due to my interest in truly understanding math and physics concepts and improving a lot during the process of learning both here and at school in the same time. My dream is to research...

Assuming that the temperature in the tire suddenly rises. My question is that would that cause the contact surface area between the tires and the floor increase, decrease, or stay the same? (given that the volume of air in the tires is a constant and cannot be changed) Also, why?