Recent content by kris2fer

Really? The equation i get is mgh = 0.5mv2 + umgd Solve for v and you should get about 5.956173268m/s.

You don't need the "d" term and try adding the 1.5 term instead of subtracting since there's thermal energy at the bottom of the ramp.

Yes.

He used +9.8 instead of -9.8.

What numbers do you plug in for vertical motion?

Sorry, my bad. I meant your velocity here is weird. How'd you get 15m/s for this if 15m/s is the velocity in horizontal direction? Also how is a metre subtracting a metre/second?

Where'd the 60 come from?

Are you sure you're using the right velocity value in the vertical equation?

The 12m the question refers to is the horizontal displacement of the projectile, not the vertical one. You used the equation for vertical motion of the pebble.

What kinematics formulas do you know that may be relevant to this problem?

So does that mean the question is faulty since the inverse is not a function?

Homework Statement Given f(x) = x2+3x+2, what is f-1(f(x))? Homework Equations The Attempt at a Solution Algebraically, getting f-1(x) is as follows: y=x2+3x+2 x=y2+3x+2 y=+/-√(x+0.25)-1.5 f-1(x)=+/-√(x+0.25)-1.5 f-1(f(x))=+/-√(x2+3x+2+0.25)-1.5...

You're assuming that the block goes only on the table. You need to take into account its total energy when compressed and its total energy when hitting the ground.