if you meusure the energy of one particle in the ##|1,1>## state it would be different to one of the ##|2,0>## state, but the total energy is the same.
i was confused because i thought, if a energy level is degenerate, there have to be several states. so is a degenerate state always a linear...
ok i have another question: if i make the second excited state with this tensor product raising operator, i get a linear combination of ## |2,0>##, ## |0,2>## and ## |1,1>##. Is that THE excited state? i thought ## 1/\sqrt{2} (|2,0> + |0,2>)## and ## |1,1>## would be separate states
hy physics forum, I am doing an advanced qm course, but i still have some doubts about the correct formalism and so on..
so i have this problem of a one-dimensional harm. oscillator including 2 bosons.
the hamiltonian would thus be ## \hat{H}=1/2 (\hat{p_1}^2+\hat{p_2}^2+\omega...