Recent content by KVat390

  1. K

    Solving Kepler's Third Law for Period - 6.7E6m

    A Revision to my previous post The equation is 4pi^2/T^2=GM/R^3 not 4pi/T^2=GM/R^3 I changed my answer to 5.46 periods 39.48/T^2=(3.98866E14)/(3.00763E20) T^2=39.48/1.33x10^-6 sqrt of T=sqrt of 39.48/1.33x10^-6 T=5.45×10^3 periods/earth years Is my answer correct?
  2. K

    Solving Kepler's Third Law for Period - 6.7E6m

    4∏/T^2=GM/R^3 4∏/T^2=(6.67×10^-11)(5.98×10^24)/(6.7×10^6)^3 12.57/T^2=(3.98866E14)/(3.00763E20) 12.57/T^2=1.326180414E-6 T^2=1.66700878E-5 T=.0040829019 Is this answer correct?
  3. K

    Solving Kepler's Third Law for Period - 6.7E6m

    Homework Statement Find the period of a satellite that is in orbit 6.7×10^6 meters from the center of the earth? Homework Equations P^2=R^3 P=period and R=average distance The Attempt at a Solution so far I have tried P^2=(6.7×10^6)^3 then sqrt of (P^2)=sqrt of (3.00763×10^20)...