The curve y=x^4-2x^3-2x^2-2x has a bitangent. I need to find the equation of this line.
First, I started off by computing the slope. Since it touches two points on the curve, their slopes should be the same.
So, I have the equation 4x^3_1-6x^2_1-4x_1-2=4x^3_2-6x^2_2-4x_2-2
I got up to the point...