Recent content by laestat

just a random browse n got into it..didnt get to see when were these published in the forum..

seems you ve done it without any calorimeter or any insulation.. heat loss through radiation and convection could add to erraneous situations..

hi, nope.. it aint made right..will post for, if requested for..

sorry. its oven, my bad..

yep..there is.. but try relating entropy changes.. there are change in entropy relations with volume, pressure & temp..no need to go for ΔT values as Temperature is made constant by electric resistance heater... i ll try to solve it when i find time & post them..

hi, water drop on a table at 0 to 100C, where, the droplet disappearing is due to the air in the room which sweeps off the water drop layer by layer, if the air is of high humid - saturated condition or in the presence of a large volume of water presence, then, you would find it staying for...

hi, specific volume of vapour at super-heated condition is less than at saturated vapour condition, hence, super-heated steam is easily transferable(higher KE), that is why, these are applied in boilers as they are carried at a faster rate & the energy carried by each vapour part is higher...

hi, specific volume of vapour at super-heated condition is less than at saturated vapour condition, hence, super-heated steam is easily transferable(higher KE), that is why, these are applied in boilers as they are carried at a faster rate & the energy carried by each vapour part is higher...

the owen is a constant heating device, water upon constant heating beyond the Tsat will yield to super-heated tendencies, meaning the cup becomes empty & the owen is filled with steam at super-heated temperatures and the pressure rises. The Latent heat of vapourization is surpassed by constant...

hi, the question has given mass as 2kg, this helps in finding results from the sp. volume/sp.enthalpy from the steam tables..at 80C find hf & hg and similarly for sp.volume along with the quality, find the total enthalpy and volume at 80C, then, since, its a closed tank, the volume of...

try change in entropy(at constant temp, the volume remains const as this is a rigid tank)= change in heat transfer/temperature(constant) & you get, the change in heat transfer as the rate of Electrical energy supplied by the electrical resistance placed..