Heat Engine with Finite Heat Capacity- Is my answer correct?

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Homework Help Overview

The discussion revolves around a heat engine utilizing a metal block as a heat reservoir and the ocean as a cold reservoir. The original poster seeks verification of their derived formula for the maximum work done by the engine, expressed in terms of the initial temperature, cold reservoir temperature, and heat capacity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster presents their derivation of work done by the engine, referencing Carnot efficiency and integrating over temperature changes. Some participants express uncertainty about the correctness of the approach, while others indicate they are struggling with similar problems.

Discussion Status

The discussion is ongoing, with mixed responses regarding the correctness of the original poster's formula. Some participants express confidence in the derivation, while others challenge its accuracy, suggesting that further clarification or alternative perspectives may be needed.

Contextual Notes

Participants are navigating the complexities of heat engines with finite heat capacities, and there is mention of related problems that may influence their understanding. The original poster's request for verification highlights the uncertainty in their solution.

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1. A heat engine is run with a large block of metal as a reservoir with initial temperature T_i and constant heat capacitance C. The ocean is used as a cold reservoir, with constant temperature T_0. What is the maximum work that could be done by the engine in terms of T_i T_0 and C
2. C = \frac{dQ}{dT} For one cycle of the engine: Efficiency E = \frac{dW}{dQ}Here's My attempt: (Can someone please verify if my answer is correct?)
If E = \frac{dW}{dQ} for one cycle
Then:
E = \frac{dW}{CdT}
dW = CE(T)dT where E(T) = formula for Carnot Efficiency = \frac{T - T_0}{T}

Adding up the work done in every cycle for every infinitessimal change in the metal block's temp gives:

W = C\int_{T_0}^{T_i} E(T)dT

W = C\int_{T_0}^{T_i} \frac{T - T_0}{T}dT

W = C\int_{T_0}^{T_i} 1 - \frac{T_0}{T} dT

W = C((T_i- T_0) - T_0\ln(\frac{T_i}{T_0}))


Does this formula look correct?
 
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bumping the thread...
 
Wow..

I can't find anything wrong. I have been in trouble with this problem. (also with two-finite heat reservoir problem). I think this is correct...
 
hi, nope.. it aint made right..will post for, if requested for..
 

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