Recent content by lastdayx52
-
L
How Can I Calculate Arc Length Without a Calculator?
OH... I added wrong... wow... Stupid mistakes FTL... Thanks all!- lastdayx52
- Post #6
- Forum: Calculus and Beyond Homework Help
-
L
How Can I Calculate Arc Length Without a Calculator?
Yes that gives me: However, what good is that, since there's still a 1 in there? I can't squareroot it to simplify... You do get 1/2, but I added a 1, therefore 3/2.- lastdayx52
- Post #4
- Forum: Calculus and Beyond Homework Help
-
L
How Can I Calculate Arc Length Without a Calculator?
How in gods name do I do that? I attempted that integral and... it just can't be integrated! What I tried: That doesn't help one bit... How do I do this? NOTE: No graphing calculator is to be used.- lastdayx52
- Thread
- Arc Arc length Calculators Length
- Replies: 5
- Forum: Calculus and Beyond Homework Help
-
L
How to Integrate x*ln(2x) and x^2/(x^2-4)?
LOL haha... See I did that, but stupidly thought the integral of 1 = 1, and when checked against the calculator, it was obviously not correct. haha... Thanks! =P- lastdayx52
- Post #5
- Forum: Calculus and Beyond Homework Help
-
L
How to Integrate x*ln(2x) and x^2/(x^2-4)?
Got a: \frac{x^2*(2*ln(2)-1)}{4}+\frac{x^2*ln(x)}{2} + C Checked on calculator, and was correct. Thank you! Now for b, that doesn't help me at all... >.>- lastdayx52
- Post #3
- Forum: Calculus and Beyond Homework Help
-
L
How to Integrate x*ln(2x) and x^2/(x^2-4)?
a. \int x*ln(2x) dx b. \int \frac{x^2}{x^2-4} dx My Attempt: a. I have abs. no clue how to start it off. Do you start it off using integration by parts? b. Same with this. I don't know how to start it off. "Random" Questions: 1) What does...- lastdayx52
- Thread
- Integrals
- Replies: 4
- Forum: Calculus and Beyond Homework Help