Recent content by lazyboi605

Also i don't understand how to find the time to max height. because it will still move after it accelerate.

Would i need to minus 33, because i am trying to find the time passed from initial upward acceleration stopping.

I am using velocity/gravity, but it don't seem to work out.

Homework Statement A model rocket takes off from ground level accelerating upward at 4.0 g. This upward acceleration lasts for 33 s. Afterward the rocket continues upward, eventually stops rising, then falls back to the ground. How much time passes from the initial upward acceleration...

i solved it. by finding the first velocity d/t. then the second velocity is 2(d2/t2) - v1. then acceleration is vf - vo over time

average acceleration over the entire interval

if u add the total distance and time, you only get an average velocity of one interval. The motion changes velocity.

can you show me what equation u used?

Homework Statement An object moving with a constant acceleration travels 13 m in 7.8 s. The acceleration is then changed and the object covers an additional 34 m in 1.7 s. What is the average acceleration of the object over the entire interval described? Homework Equations Xf1 = 1/2(vo +vf)t...