Finding average acceleration over an time interal

  • Thread starter lazyboi605
  • Start date
  • #1

Homework Statement



An object moving with a constant acceleration travels 13 m in 7.8 s. The acceleration is then changed and the object covers an additional 34 m in 1.7 s. What is the average acceleration of the object over the entire interval described?

Homework Equations



Xf1 = 1/2(vo +vf)t
a=(vo +vf)/t

The Attempt at a Solution



vf1 =2(13)/7.8
vo =2(34)(1.7) - 44.2
a = (115.6-44.2)9.5

im not sure how to solve this problem
 

Answers and Replies

  • #2
61
0
take it back to orginial equation... you can not break down like that...
here is my answer for you: 0.52m/s/s (starting at 0)
however please consider the starting speed...
 
  • #3
can you show me what equation u used?
 
  • #4
61
0
lol, this has nothing to do with acceleration equation...
you just simply add 2 total distance together and divid them by total time to get average v, then v/t=a
 
  • #5
if u add the total distance and time, you only get an average velocity of one interval. The motion changes velocity.
 
  • #6
61
0
do you mean average accerleration over entire time or something else? i am not quit getting it...
 
  • #7
average acceleration over the entire interval
 
  • #8
61
0
then my answer should be right...
 
  • #9
61
0
you said average...
 
  • #10
i solved it. by finding the first velocity d/t. then the second velocity is 2(d2/t2) - v1. then acceleration is vf - vo over time
 
  • #11
61
0
dude i told you....
 

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