Finding average acceleration over an time interal

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Homework Help Overview

The problem involves calculating the average acceleration of an object that experiences two different phases of motion, covering specified distances in given time intervals. The context is rooted in kinematics, specifically focusing on acceleration and velocity.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss different methods for calculating average acceleration, with some suggesting to revert to original equations while others propose summing distances and dividing by total time to find average velocity. Questions arise regarding the interpretation of average acceleration over the entire interval and the role of initial velocity.

Discussion Status

The discussion is ongoing, with various interpretations of how to approach the problem. Some participants have provided calculations and answers, while others are seeking clarification on the definitions and methods being used. There is no explicit consensus on the correct approach yet.

Contextual Notes

Participants are navigating assumptions about initial conditions and the nature of the motion, indicating potential constraints in the problem setup. There is a noted confusion regarding the distinction between average acceleration and average velocity.

lazyboi605
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Homework Statement



An object moving with a constant acceleration travels 13 m in 7.8 s. The acceleration is then changed and the object covers an additional 34 m in 1.7 s. What is the average acceleration of the object over the entire interval described?

Homework Equations



Xf1 = 1/2(vo +vf)t
a=(vo +vf)/t

The Attempt at a Solution



vf1 =2(13)/7.8
vo =2(34)(1.7) - 44.2
a = (115.6-44.2)9.5

im not sure how to solve this problem
 
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take it back to orginial equation... you can not break down like that...
here is my answer for you: 0.52m/s/s (starting at 0)
however please consider the starting speed...
 
can you show me what equation u used?
 
lol, this has nothing to do with acceleration equation...
you just simply add 2 total distance together and divid them by total time to get average v, then v/t=a
 
if u add the total distance and time, you only get an average velocity of one interval. The motion changes velocity.
 
do you mean average accerleration over entire time or something else? i am not quit getting it...
 
average acceleration over the entire interval
 
then my answer should be right...
 
you said average...
 
  • #10
i solved it. by finding the first velocity d/t. then the second velocity is 2(d2/t2) - v1. then acceleration is vf - vo over time
 
  • #11
dude i told you...
 

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